This calculator estimates the energy required for water heating from an initial to a final temperature and the time needed for heating based on heater power. It can also account for heater efficiency and estimate energy cost if a tariff is provided. The calculator is suitable for domestic water heaters, boilers, storage tanks, and similar systems.
Determine temperature rise. The calculation starts with the temperature difference ΔT = Tfinal − Tinitial, expressed in degrees Celsius. Only a positive temperature rise is considered, because cooling does not require heating energy.
Convert water volume to thermal energy. Water mass is assumed equal to its volume in liters (1 L ≈ 1 kg). The required thermal energy is calculated from the physical relation Q = c × m × ΔT, where c is the specific heat capacity of water. For convenience, this is converted into kilowatt-hours using a constant factor, giving Qwater in kWh.
Account for heater efficiency. If efficiency η is specified, the energy taken from the source is higher than the heat delivered to the water. The calculator applies Qsource = Qwater / η. For electric heaters, efficiency is often close to 100%, while combustion-based systems usually have lower values.
Calculate heating time. Heating time is obtained by dividing the required source energy by the heater's useful thermal power: t = Qsource / P, where P is in kW. The result is shown in hours and minutes, assuming constant power during heating.
Estimate energy cost. If a tariff per kWh is provided, the calculator multiplies it by Qsource. This gives an approximate cost for one complete heating cycle, useful for comparing different heater sizes or energy sources.
Typical reference values. Cold tap water is often in the range of 5-15 °C, while domestic hot water is commonly heated to 50-60 °C. Small household electric heaters typically have powers from 1.5 to 3 kW. These assumptions align with common European practice described in EN energy efficiency and domestic hot water guidelines.
The required energy is directly proportional to water volume. Doubling the volume doubles the energy demand, and with the same heater power, the heating time also doubles.
For electric resistance heaters, efficiency is usually close to 100%, so its influence is minimal. For gas, oil, or solid-fuel boilers, efficiency significantly affects both energy consumption and cost.
No. The calculation assumes ideal conditions without heat losses to the environment. In real systems, heat losses may slightly increase the actual heating time and energy use.
It is best suited for batch heating of a known water volume. For instantaneous heaters, flow rate and temperature rise should be evaluated using a different calculation approach.
The results are well suited for preliminary estimates and comparisons. Final system sizing should also consider standby losses, duty cycles, safety margins, and manufacturer specifications.